(编辑:jimmy 日期: 2024/12/31 浏览:2)
在某些情况下熟悉SQL Server 通配符的使用可以帮助我们简单的解决很多问题。
--使用_运算符查找Person表中以an结尾的三字母名字 USEAdventureWorks2012; GO SELECT FirstName, LastName FROM Person.Person WHERE FirstName LIKE'_an' ORDER BY FirstName; ---使用[^]运算符在Contact表中查找所有名字以Al开头且第三个字母不是字母a的人 USEAdventureWorks2012; GO SELECT FirstName, LastName FROM Person.Person WHERE FirstName LIKE'Al[^a]%' ORDER BY FirstName; ---使用[]运算符查找其地址中有四位邮政编码的所有Adventure Works雇员的ID和姓名 USEAdventureWorks2012; GO SELECT e.BusinessEntityID, p.FirstName, p.LastName, a.PostalCode FROMHumanResources.EmployeeAS e INNER JOIN Person.PersonAS pON e.BusinessEntityID= p.BusinessEntityID INNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityID INNER JOIN Person.AddressAS aON a.AddressID= ea.AddressID WHERE a.PostalCodeLIKE'[0-9][0-9][0-9][0-9]';
结果集:
EmployeeID FirstName LastName PostalCode ---------- --------- --------- ---------- 290 Lynn Tsoflias 3000
--将一张表中名字为中英文的区分出来(借鉴论坛中的代码) create table tb(namenvarchar(20)) insert into tbvalues('kevin') insert into tbvalues('kevin刘') insert into tbvalues('刘') select *,'Eng'from tbwherepatindex('%[a-z]%',name)>0and(patindex('%[吖-坐]%',name)=0) union all select *,'CN'from tbwherepatindex('%[吖-坐]%',name)>0andpatindex('%[a-z]%',name)=0 union all select *,'Eng&CN'from tbwhere(patindex('%[吖-坐]%',name)>0)andpatindex('%[a-z]%',name)>0
结果集:
name -------------------- ------ kevin Eng 刘 CN kevin刘 Eng&CN (3 row(s) affected)